\cos(bx)dx&line2=\mathrm{Solution:\:}\frac{1}{2}(\frac{1}{a%2Bb}\sin(ax%2Bbx)%2B\frac{1}{a-b}\sin(ax-bx))%2BC "What is the integral of cos(ax)cos(bx) ?")
What is the integral of cos(ax)cos(bx) ?
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Integration (Calculus) - Notes
SOLVED: Part 2: Integration by the Method of Undetermined Coefficients 1) Let A and B be real numbers and consider the integral cos(Ax) eBx dx. By considering the derivative of flx) =
\cos(bx)dx&line2=\mathrm{Solution:\:}\frac{1}{2}(-\frac{1}{a%2Bb}\cos(ax%2Bbx)-\frac{1}{a-b}\cos(ax-bx))%2BC "What is the integral of sin(ax)cos(bx) ?")
What is the integral of sin(ax)cos(bx) ?
SOLVED: 5: General Integration Formulas cos ax dx = a sin ax+C sin ax dx = cos ax +C | sec 2ax dx = tan ax+C J csc ?ax dx = –
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